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Worksheets Quiz
Read Hebdon Unit 2
Worksheet #1 Approaching Equilibrium
Read unit II your textbook. Answer all of the questions. Do not start the questions until you have completed the reading. Be prepared to discuss your answers next period.
In a forward reaction, the reactants collide to produce products and it goes from left to right. In a reverse reaction, the products collide to produce reactants and it goes form right to left. 3. Why does the forward reaction rate decrease as equilibrium is approached? As the reaction goes to the right, the reaction concentration decreases and therefore, there are less reactant collisions causing the forward rate to decrease. 4. What are the characteristics of equilibrium? Forward rate is equal to the reverse rate. The concentration of reactants and products are constant.(not equal) Macroscopic properties are constant (color, mass, density, pressure, concentrations).
If a catalyst was added to the reaction, what would happen to the PE Diagram, the forward rate, and the reverse rate?
PE Diagram The activation energy would decrease Forward rate Increase Reverse rate Increase
One mole of very cold, colorless N 2 O4 (g) is placed into a 1 glass container of room temperature. The reaction: N 2 O4 (g) ⇋ 2 N02 (g) H= +58KJ
The container will gradually increase the intensity of brown and then remain constant after 15 seconds. 20. Calculate the rate of N 2 O 4 consumption in (M/s) over the first 5s period and then the second 5s period. 0-5 sec. rate = 1 – 0. M = 0 M / s 5 sec 5-10 sec. rate = 0 – 0. M = 0 M / s 5 sec
Why is the rate greater over the first five minutes compared to the second five minutes (think in terms of reactant and product concentrations?
The reactant concentration has decreased and the product concentration increased. The forward rate has decreased and the reverse rate increased and because of this the overall net rate has decreased.
How does the rate of formation of N0 2 compare to the rate of consumption of N 2 O 4? Remember, if you measure the reactants or products, it is still the overall rate. It is twice as great because of the stoichiometric relationship. 2moles NO 2 1mole N 2 O 4
[N 2 O 4 ]= 0 M Are they equal? No! [N0 2 ] = 0 M
Worksheet #2 LeChatelier’s Principle
e
N 2 O 4 (g) ⇋ 2NO2(g) H = + 92 KJ
Shifts Shifts to Favor the Stress [N 2 O 4 ] [NO 2 ] Right or Left Reactants or Products
4HCl (g) + O2 (g) ⇋ 2H 2 O(g) + 2Cl2 (g) + 98 KJ
Shifts Shifts to Favour the Stress [O 2 ] [H 2 O] [HCl] Right or Left Reactants or Products
CaCO3 (s) + 170 KJ ⇋ CaO (s) + CO2 (g)
NH 3 addition increases decreases increases increases removal decreases increases decreases decreases
O 2 addition decreases increases increases increases
removal increases decreases decreases decreases
NO addition increases increases increases decreases
removal decreases decreases decreases increases
H 2 O addition increases increases decreases increases removal decreases decreases increases decreases
Increase in temperature: increases increases decreases decreases
Decrease in temperature: decreases decreases increases increases
Increase Presssure: increases increases increases increases
Decrease in pressure: decreases decreases decreases decreases We increased the volume- all concentrations go down
Addition of a catalyst: nochange nochange nochange nochange
An inert gas is added: nochange nochange nochange nochange
Worksheet #4 Le Chatelier’s Principle
State the direction in which each of the following equilibrium systems would be shifted upon the application of the following stress listed beside the equation.
Consider the following equilibrium system:
3 H2 (g) + N2 (g) ⇋ 2 NH3 (g) + Heat.
State what effect each of the following will have on this system:
Forward Rate has decreases Reverse Rate has decreases.
Consider the following equilibrium system
H2 (g) + I2 (g) ⇋ 2 HI (g)
State what effect each of the following will have on this system in terms of shifting.
Consider the following equilibrium system:
3 Fe (s) + 4 H 2 O (g) <------> Fe 3 O4 (s) + 4 H2 (g)
State what effect each of the following will have on this system in terms of shifting. 21. The volume of the vessel is decreased nochange 22. The pressure is decreased nochange
Consider the following equilibrium: 2NO (g) + Br2 (g) + energy <------> 2NOBr (g)
State what affect each of the following will have on this system in terms of shifting. 26. The volume of the vessel is increased left 27. The pressure is decreased left 28. More Br 2 is added to the system right 29. Some NO is removed from the system left 30. A catalyst is added to the system nochange Consider the following equilibrium: Some CO was added to the system and a new equilibrium was established. 2CO (g) + O2 (g) <------> 2CO2 (g) + energy 31. Compare to the original system, the rates of the forward and reverse reactions of the new equilibrium. Forward Rate has increases Reverse Rate has increases
shift color change Increase in [H+] right Orange Increase in [CrO 4 2-] right Increase in [Cr 2 O 7 2-] left Decrease in [H+] left Yellow Decrease in [CrO 4 2-] left Increase in temperature right Orange Decrease intemperature left Yellow Add HCl (aq) right Orange Add NaOH left Yellow OH- reacts with H+ and lowers [H+] causing the reaction to shift left.
Cu(OH)2 (aq) +4 H 2 O (l) ⇋ Cu(H 2 O) 4 2+(aq) +2 OH-(aq) + 215 kJ violet light blue
Describe how the above equilibrium will shift after each stressbelow:
shift colorchange Increase in [Cu(H 2 O) 4 2+] left Add NaOH left Violet Increase in [Cu(OH) 2 ] right Decrease in [Cu(H 2 O) 4 2+] right Decrease in[Cu(OH) 2 ] left Increase temperature left Violet Decrease temperature right Light Blue AddKCl (aq) no change nochange AddHCl (aq) right Light Blue
4 HCl (g)+ 2 O2 (g) ⇋ 2 H 2 O (l) + 2 Cl 2 (g) + 98 kJ (yellow)
Describe how the above equilibrium will shift after each stress below:
shift color change Increase in temperature left clear Increase [HCl] right yellow Decrease in [Cl 2 ] right Decrease temperature right yellow Add Ne at constant volume No Change
Cu+ (aq) + Cl-(aq) ⇋ CuCl (s) ΔH = + 98 kJ (green)
Describe how the above equilibrium will shift after each stress below: Cu+ is green shift color change Increase in temperature right less green Increase [HCl] right less green Add NaCl right less green Decrease temperature left green Add NaOH (aq) left clear (reacts with HCl)
(check your solubility table for a possible reaction)
Add CuCl(s) no change no change Add AgNO 3 (aq) left green
(check your solubility table for a possible reaction)
Add CuNO 3 (aq) right because it contains the Cu+ ion.